Saturday, August 3, 2024

Hack cyber at.gov.pt ( And Again I was using this url 62.28.254.198/postsendRequest(req,%20j)/auth/access_token/client_credentials/id/client_secret but I already hv the username id (json obj) so I´m doing something wrong but, it looks since I´m not in Apache I cant´t migrate forward their server )

 


https://stackoverflow.com/questions/45642893/how-to-get-access-token-for-an-api-by-using-post-method-in-javascript

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Hack truque trick decode elliptic curve

  import hashlib def msg_to_int(msg: str):     return int(hashlib.sha256(msg.encode()).hexdigest(), 16) P_recovered = k_inv * C m_recovered ...