Friday, June 12, 2026

António Costa Influencer novas escutas 2026 Portugal Intel

 




HTML script code for the elliptic curve decryption

 




<!DOCTYPE html>

<html>

<head>

<meta charset="UTF-8">

<title>ECC Decode Tool (k⁻¹ · C)</title>

<style>

    body {

        font-family: Arial, sans-serif;

        background: #f0f0f0;

        padding: 20px;

    }

    .box {

        background: white;

        padding: 15px;

        border-radius: 8px;

        margin-bottom: 20px;

        box-shadow: 0 0 5px rgba(0,0,0,0.1);

    }

    input {

        width: 100%;

        padding: 8px;

        margin-top: 5px;

        margin-bottom: 10px;

        border-radius: 5px;

        border: 1px solid #aaa;

    }

    button {

        padding: 10px 20px;

        background: #0078ff;

        color: white;

        border: none;

        border-radius: 5px;

        cursor: pointer;

    }

    button:hover { background: #005fcc; }

    pre {

        background: #222;

        color: #0f0;

        padding: 10px;

        border-radius: 5px;

        overflow-x: auto;

    }

</style>

</head>

<body>


<h2>ECC Decode Tool — Compute P = k⁻¹ · C</h2>


<div class="box">

    <label>C.x:</label>

    <input id="cx" type="text">


    <label>C.y


    <label>Scalar k:</label>

    <input id="k" type="number">


    <button onclick="decodeECC()">Decode</button>

</div>


<div class="box">

    <h3>Decoded Output</h3>

    <pre id="output"></pre>

</div>


<script>

// secp256k1 parameters

const p = BigInt("0xFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFEFFFFFC2F");

const n = BigInt("0xFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFEBAAEDCE6AF48A03BBFD25E8CD0364141");


// Point class

class Point {

    constructor(x, y) { this.x = x; this.y = y; }

}


// Modular exponentiation

function modPow(base, exp, mod) {

    let r = 1n;

    base %= mod;

    while (exp > 0) {

        if (exp & 1n) r = (r * base) % mod;

        base = (base * base) % mod;

        exp >>= 1n;

    }

    return r;

}


// Modular inverse

function modInv(a, m) {

    return modPow(a, m - 2n, m);

}


// Point addition

function pointAdd(P, Q) {

    if (P === null) return null) return P;


    if (P.x === Q.x && P.y !== Q.y) return null;


    let m;

    if (P.x === Q.x && P.y === Q.y) {

        m = (3n * P.x * P.x) * modInv(2n * P.y, p) % p;

    } else {

        m = (Q.y - P.y) * modInv(Q.x - P.x, p) % p;

    }


    const rx = (m*m - P.x - Q.x) % p;

    const ry = (m*(P.x - rx) - P.y) % p;

    return new Point((rx+p)%p, (ry+p)%p);

}


// Scalar multiplication

function scalarMult(k, P) {

    let R = null;

    let A = P;

    while (k > 0n) {

        if (k & 1n) R = pointAdd(R, A);

        A = pointAdd(A, A);

        k >>= 1n;

    }

    return R;

}


// Convert integer → text

function intToText(x) {

    let hex = x.toString(16);

    if (hex.length % 2) hex = "0" + hex;

    let bytes = new Uint8Array(hex.match(/.{1,2}/g).map(b => parseInt(b,16)));

    return new TextDecoder().decode(bytes);

}


// Main decode function

function decodeECC() {

    const cx = BigInt(document.getElementById("cx").value);

    const cy = BigInt(document.getElementById("cy").value);

    const k = BigInt(document.getElementById("k").value);


    const C = new Point(cx, cy);


    const k_inv = modInv(k, n);

    const P = scalarMult(k_inv, C);


    let recovered = "";

    try { recovered = intToText(P.x); }

    catch { recovered = "(invalid UTF‑8 data)"; }


    document.getElementById("output").textContent =

        "k⁻¹ mod n:\n" + k_inv + "\n\n" +

        "Decoded point P:\n" + JSON.stringify(P, null, 2) + "\n\n" +

        "Recovered message:\n" + recovered;

}

</script>


</body>

</html>

Elliptic curve hack decode script AI

 import numpy as np


def decode_circle(p1, p2, p3):

    x1,y1 = p1

    x2,y2 = p2

    x3,y3 = p3


    D = 2 * np.linalg.det([

        [x1, y1, 1],

        [x2, y2, 1],

        [x3, y3, 1]

    ])


    h = ((x1**2+y1**2)*(y2-y3) +

         (x2**2+y2**2)*(y3-y1) +

         (x3**2+y3**2)*(y1-y2)) / D


    k = ((x1**2+y1**2)*(x3-x2) +

         (x2**2+y2**2)*(x1-x3) +

         (x3**2+y3**2)*(x2-x1)) / D


    r = np.sqrt((x1-h)**2 + (y1-k)**2)


    return h, k, r


import numpy as np


def decode_point(x, y, h, k, R):

    d = np.sqrt((x - h)**2 + (y - k)**2)

    if np.isclose(d, R):

        return "on", d

    elif d < R:

        return "inside", d

    else:

        return "outside", d


def reconstruct_circle(p1, p2, p3):

    x1,y1 = p1

    x2,y2 = p2

    x3,y3 = p3


    D = 2 * np.linalg.det([

        [x1, y1, 1],

        [x2, y2, 1],

        [x3, y3, 1]

    ])


    h = ((x1**2+y1**2)*(y2-y3) +

         (x2**2+y2**2)*(y3-y1) +

         (x3**2+y3**2)*(y1-y2)) / D


    k = ((x1**2+y1**2)*(x3-x2) +

         (x2**2+y2**2)*(x1-x3) +

         (x3**2+y3**2)*(x2-x1)) / D


    R = np.sqrt((x1-h)**2 + (y1-k)**2)


    return h, k, R















Thursday, June 11, 2026

Hack truque trick decode elliptic curve

 









import hashlib


def msg_to_int(msg: str):

    return int(hashlib.sha256(msg.encode()).hexdigest(), 16)


P_recovered = k_inv * C

m_recovered = P_recovered.x # or y, depending on your encoding

















<!DOCTYPE html>

<html>

<head>

<meta charset="UTF-8">

<title>Reversible ECC k·P Tool</title>

<style>

    body {

        font-family: Arial, sans-serif;

        background: #f4f4f4;

        padding: 20px;

    }

    h2 { color: #333; }

    .box {

        background: white;

        padding: 15px;

        border-radius: 8px;

        margin-bottom: 20px;

        box-shadow: 0 0 5px rgba(0,0,0,0.1);

    }

    input, textarea {

        width: 100%;

        padding: 8px;

        margin-top: 5px;

        margin-bottom: 10px;

        border-radius: 5px;

        border: 1px solid #aaa;

    }

    button {

        padding: 10px 20px;

        background: #0078ff;

        color: white;

        border: none;

        border-radius: 5px;

        cursor: pointer;

    }

    button:hover { background: #005fcc; }

    pre {

        background: #222;

        color: #0f0;

        padding: 10px;

        border-radius: 5px;

        overflow-x: auto;

    }

</style>

</head>

<body>


<h2>Reversible ECC k·P Encryption Tool</h2>


<div class="box">

    <label>Message:</label>

    <textarea id="msg" rows="3"></textarea>


    <label>Scalar k:</label>

    <input id="k" type="number" value="123456789">


    <button onclick="runECC()">Encrypt + Decrypt</button>

</div>


<div class="box">

    <h3>Results</h3>

    <pre id="output"></pre>

</div>


<script>

// --- secp256k1 parameters ---

const p = BigInt("0xFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFEFFFFFC2F");

const n = BigInt("0xFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFEBAAEDCE6AF48A03BBFD25E8CD0364141");

const Gx = BigInt("55066263022277343669578718895168534326250603453777594175500187360389116729240");

const Gy = BigInt("32670510020758816978083085130507043184471273380659243275938904335757337482424");


// Point object

class Point {

    constructor(x, y) { this.x = x; this.y = y; }

}


// Modular inverse

function modInv(a, m) {

    return modPow(a, m - 2n, m);

}


// Modular exponentiation

function modPow(base, exp, mod) {

    let r = 1n;

    base %= mod;

    while (exp > 0) {

        if (exp & 1n) r = (r * base) % mod;

        base = (base * base) % mod;

        exp >>= 1n;

    }

    return r;

}


// Point addition

function pointAdd(P, Q) {

    if (P === null) return Q;

    if (Q === null) return P;


    if (P.x === Q.x && P.y !== Q.y) return null;


    let m;

    if (P.x === Q.x && P.y === Q.y) {

        m = (3n * P.x * P.x) * modInv(2n * P.y, p) % p;

    } else {

        m = (Q.y - P.y) * modInv(Q.x - P.x, p) % p;

    }


    const rx = (m*m - P.x - Q.x) % p;

    const ry = (m*(P.x - rx) - P.y) % p;

    return new Point((rx+p)%p, (ry+p)%p);

}


// Scalar multiplication

function scalarMult(k, P) {

    let R = null;

    let A = P;

    while (k > 0n) {

        if (k & 1n) R = pointAdd(R, A);

        A = pointAdd(A, A);

        k >>= 1n;

    }

    return R;

}


// Convert text → integer

function textToInt(txt) {

    let bytes = new TextEncoder().encode(txt);

    let hex = "0x" + Array.from(bytes).map(b => b.toString(16).padStart(2,"0")).join("");

    return BigInt(hex);

}


// Convert integer → text

function intToText(x) {

    let hex = x.toString(16);

    if (hex.length % 2) hex = "0" + hex;

    let bytes = new Uint8Array(hex.match(/.{1,2}/g).map(b => parseInt(b,16)));

    return new TextDecoder().decode(bytes);

}


// Main ECC reversible process

function runECC() {

    const msg = document.getElementById("msg").value;

    const k = BigInt(document.getElementById("k").value);


    const m = textToInt(msg) % n;

    const P = scalarMult(m, new Point(Gx, Gy));


    const C = scalarMult(k, P);

    const k_inv = modInv(k, n);

    const P2 = scalarMult(k_inv, C);


    const recovered = intToText(P2.x);


    document.getElementById("output").textContent =

        "Message integer m:\n" + m + "\n\n" +

        "Point P = m·G:\n" + JSON.stringify(P, null, 2) + "\n\n" +

        "Encrypted C = k·P:\n" + JSON.stringify(C, null, 2) + "\n\n" +

        "Decrypted P = k⁻¹·C:\n" + JSON.stringify(P2, null, 2) + "\n\n" +

        "Recovered message:\n" + recovered;

}

</script>


</body>

</html>



Wednesday, June 10, 2026

Portugal Intel RTP E ANACOM intranet login

 https://stat.anacom.pt/pt-PT/SignIn?returnUrl=%2Fpt-PT%2F

https://as.rtp.pt/adfs/ls/?client-request-id=3c4663cd-83ac-467d-bd5d-5777dcb8092c&username=&wa=wsignin1.0&wtrealm=urn%3afederation%3aMicrosoftOnline&wctx=estsredirect%3d2%26estsrequest%3drQQIARAA02I21DO0UjEzSUxOMTYx0E0zMjbUNbE0Mte1NDU30zUwNTIyMDY1sLBMtCwS4hI4m-xms6a51m1vbHj5nR2cOrMY2YpKCvQKSlYxSmSUlBQUW-nrZ-aVFCXmpZboQWT0dzAyXmBkfMHIeIuJ39-xtCTDCETkF2VWpX5iYi0sTS2qnMWsYpmaYplknmaom5hoZq5rYmBhqJtonpSqm2JqZGpkbp5mkmhpvopZxQACjHRBJIRIhrFgYBOzSqqxpWGioYWBbkqyiYWuiYlRoq5FamKKroFhkqllolmqkYGBwSlmDZiT04sSCzL0cjOTi_KL89NK9JLzc_ULivLTMnNS9YpSE1NuMDNeYGF8xcJkwPiDhXERqxCXgK-9WIeCTaDHUrEKcylHU4ZTrPoebmWmmZXprmbmSYX-flnOlckW5f5lWf76xd4ZZpZl7mUWJtneyR5Jflm-thZWhhPYGD-wMXawM-ziFMcRdgd4GX7wHdpw5Nyn6xvfe2wQYHggwPBAkOGHoECHEAMA0#